Question

The area of an equilateral triangle is $64$$\sqrt{3}{cm}^2$. Find the perimeter of the triangle.

Answer 1

Let the side of the equilateral triangle be $a$ $cm$

area of the triangle

$\frac{\sqrt{3}}{4}{a}^2=64\sqrt{3}\Rightarrow a^2=\frac{4\times 64\times \sqrt{3}}{\sqrt{3}}\Rightarrow a^2=256\Rightarrow a=16$

perimeter of the triangle$=3a$$=3\times 16=48$ $cm$