The area of cross-section- length- and density of a piece of a metal of atomic weight 60 are 10-6 m 2- 1-0 m and 5 - 103 kgm -3 respectively- The number of free electrons per unit volume if every atom contributes one free electron isA- 5 - 1030 m -3B- 8 - 1028 m -3C- 4 - 1021 m -3D- 5 - 1028 m -3

The correct option is D 5 x 1028 m 3 ...

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Byju's Answer

Standard XII

Physics

Mass Energy Equivalence

The area of c...

Question

The area of cross-section, length, and density of a piece of a metal of atomic weight 60 are 10^-6 m², 1.0 m and 5 x 10³ kgm^-3 respectively. The number of free electrons per unit volume if every atom contributes one free electron is

5 x 10²⁸ m^-3

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5 x 10³⁰ m^-3

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8 x 10²⁸ m^-3

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4 x 10²¹ m^-3

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Solution

The correct option is A
5 x 10²⁸ m^-3

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Similar questions

Q. The area of cross section, length, and density of a piece of metal of atomic weight 60 are

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The area of cross-section, length, and density of a piece of a metal of atomic weight 60 are 10-6 m2, 1.0 m and 5 x 103 kgm-3 respectively. The number of free electrons per unit volume if every atom contributes one free electron is

The correct option is A 5 x 1028 m-3

The area of cross-section, length, and density of a piece of a metal of atomic weight 60 are 10^-6 m², 1.0 m and 5 x 10³ kgm^-3 respectively. The number of free electrons per unit volume if every atom contributes one free electron is

The correct option is A
5 x 10²⁸ m^-3