Question

The average translational kinetic energy of $O_2$ (relative molar mass $32$) molecules at a particular temperature is $0.048eV$. The translational kinetic energy of $N_2$ (relative molar mass $28$) molecules in $eV$ at that temperature is

• A. $0.0015$
• B. $0.003$
• C. $0.048$
• D. $0.768$

Answer 1

Answer: (C)

$0.048$

Given,

$E_{O_2}=0.048eV$

We know that,

Translational kinetic energy,

$E=\frac{3}{2}KT$

where, $k=$ Boltzmann constant

$T=$ Temperature

$\therefore E\propto T$

Since, the temperature is same for both oxygen and nitrogen

therefore, $E_{O_2}=E_{N_2}$

$\therefore E_{N_2}=0.048eV$