Question

The binding energy per nucleon of $O^{16}$ is 7.97 MeV and that of $O^{17}$ is 7.75 MeV. Then, the energy (in MeV) required to remove a neutron from $O^{17}$ is

• A. 3.52
• B. 3.64
• C. 4.23
• D. 7.86

Answer 1

The correct option is C

4.23

$O^{17}\to O^{16}{+}_O{n}^1$
$\therefore$ Energy required = Binding of $O^{17}$ - binding energy of $O^{16}=17\times 7.75-16\times 7.97=4.23MeV$