Question

The binding energy per nucleon of $O^{16}$ is 7.97 MeV and that of $O^{17}$ is 7.75 MeV. Then, the energy (in MeV) required to remove a neutron from $O^{17}$ is

• A. 3.52
• B. 3.64
• C. 4.23
• D. 7.86

Answer 1

Answer: (C)

Step 1: Given that:

The binding energy per nucleon for $O^{16}$ = $7.97MeV$

The binding energy per nucleon for $O^{17}$ = $7.75MeV$

Step 2: Calculation of energy (in MeV) required to remove a neutron from $O^{17}$ :

We have;

$O^{17}⟶O^{16}{+}_0^{1}n$

Thus,

Energy required= Binding energy per nucleon of $O^{17}$ $-$ Binding energy per nucleon of $O^{16}$ = $17\times 7.75-16\times 7.97$

= $131.75$ $-$ 127.52

= 4.23MeV

Thus,

The energy required energy (in MeV) required to remove a neutron from $O^{17}$ is $4.23MeV$Thus,

Option D) $4.23MeV$ is the correct option.