Question

The boiling point of $C_6{H}_6,C{H}_{3}OH,C_6{H}_{5}N{H}_2$ and $C_6{H}_{5}N{O}_2$ are $80{}^{\circ }C$, $65{}^{\circ }C$, $184{}^{\circ }C$ $212{}^{\circ }C$ respectively.

Which will show the highest vapour pressure at room temperature?

• A. $C_6{H}_6$
• B. $C{H}_{3}OH$
• C. $C_6{H}_{5}N{H}_2$
• D. $C_6{H}_{5}N{O}_2$

Answer 1

The correct option is B $C{H}_{3}OH$

Lower the boiling point higher is the vapour pressure.

Methanol $C{H}_{3}OH$ with a lowest boiling point will show highest vapour pressure at room temperature as it is most volatile.

Hence, the correct option is $B$