The boiling point of C6H6- CH3OH- C6H5NH2 and C6H5NO2 are 80 -C- 65 -C- 184 -C 212 -C respectively- Which will show the highest vapour pressure at room temperature-

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Raoult's Law

The boiling p...

Question

The boiling point of $C_{6} H_{6}, C H_{3} O H, C_{6} H_{5} N H_{2}$ and $C_{6} H_{5} N O_{2}$ are $80^{\circ} C$ , $65^{\circ} C$ , $184^{\circ} C$ $212^{\circ} C$ respectively.
Which will show the highest vapour pressure at room temperature?

C_{6} H_{6}

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C H_{3} O H

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C_{6} H_{5} N H_{2}

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C_{6} H_{5} N O_{2}

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Solution

The correct option is B $C H_{3} O H$
Lower the boiling point higher is the vapour pressure.

Methanol $C H_{3} O H$ with a lowest boiling point will show highest vapour pressure at room temperature as it is most volatile.

Hence, the correct option is $B$

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