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Bond Angle

The bond angl...

Question

The bond angles of $N H_{3}, N H_{4}^{+}$ and ${N H_{2}}^{-}$ are in the order:

N H_{2}^{-} > N H_{3} > N H_{4}^{+}

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N H_{4}^{+} > N H_{3} > N H_{2}^{-}

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N H_{3} > N H_{2}^{-} > N H_{4}^{+}

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N H > N H_{4}^{+} > N H_{2}^{-}

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Solution

The correct option is B $N H_{4}^{+} > N H_{3} > N H_{2}^{-}$
On increases the number of lone pairs of electrons, bond angle decreases. Therefore, the order of bond angle is

$N H_{4}^{+} > N H_{3} > {N H_{2}}^{-}$

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