Question

The brakes applied to a car produce a negative acceleration of 6 $m/s^2$. If the car takes 2 seconds to stop after applying the brakes, calculate the distance it travels during this time. (Give your answer in m)

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Answer 1

Here,

a = –6 $m/s^2$, t = 2 s and v = 0 m/s

Using the equation,

v = u + at, we get

0 = u + (–6 × 2)

u = 12 m/s

Now by using the equation

$v^2$ = $u^2$ + 2as

0 = ${12}^2$ - (2 x 6 x S)

S = 12m