Question

The capacitors $C_1,C_3,C_4,C_5$ shave a capacitance $4\mu F$ each and $C_2$ has capacitance $10\mu F$. The effective capacitance between P and Q will be :

• A. $8\mu F$
• B. $6\mu F$
• C. $4\mu F$
• D. $2\mu F$

Answer 1

The correct option is C $4\mu F$

The given circuit will represent a balanced Wheatstone bridge. So no current flow through $C_2$ and we can removed from the circuit. The corresponding equivalent circuit is shown in figure.

The effective capacitance between P and Q is $C_{PQ}=(1/C_1+1/C_5{)}^{-1}+(1/C_3+1/C_4{)}^{-1}=(1/4+1/4{)}^{-1}+(1/4+1/4{)}^{-1}=2+2=4\mu F$