The change in base current from transistor characteristics when current amplification factor $β = 100$ , with change in collector current as $1 m A$ is

0.1 m A

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1 m A

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0.01 m A

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0.001 m A

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Solution

The correct option is C $0.01 m A$
Given that,
$β = 100$
$Δ I_{c} = 1 m A$
For transistors, current amplification factor is
$β = \frac{Δ I_{c}}{Δ I_{b}}$
$Δ I_{b} = \frac{Δ I_{c}}{β}$
$Δ I_{b} = \frac{1}{100} = 10^{- 2} = 0.01 m A$

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The change in base current from transistor characteristics when current amplification factor β=100, with change in collector current as 1 mA is

The correct option is C 0.01 mAGiven that,β=100ΔIc=1 mAFor transistors, current amplification factor isβ=ΔIcΔIbΔIb=ΔIcβΔIb=1100=10−2=0.01 mA

The change in base current from transistor characteristics when current amplification factor $β = 100$ , with change in collector current as $1 m A$ is

The correct option is C $0.01 m A$
Given that,
$β = 100$
$Δ I_{c} = 1 m A$
For transistors, current amplification factor is
$β = \frac{Δ I_{c}}{Δ I_{b}}$
$Δ I_{b} = \frac{Δ I_{c}}{β}$
$Δ I_{b} = \frac{1}{100} = 10^{- 2} = 0.01 m A$