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Van't Hoff Factor

The chlorate ...

Question

The chlorate ion can disproportionate in basic solution according to reaction,
$2 C l O_{3}^{-} ⇌ C l O_{2}^{-} + C l O_{4}^{-}$
The concentration of chlorate ion present initially is $0.1 M$ .
The equilibrium concentration of perchlorate ions at $298$ K is $x$ . What is the value of $\frac{1}{x}$ ?
Given : $E_{C l O_{4}^{-} | C l O_{3}^{-}} = 0.36 V a n d E_{C l O_{3}^{-} | C l O_{2}^{-}}^{\circ} = 0.33. V A t 298 K \frac{R T}{F} = 0.06 V \sqrt{10} = 3.16$

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Solution

$H_{2} O (l) + C l O_{3}^{-} (a q) \to C l O_{4}^{-} (a q) + 2 H^{+} (a q) + 2 e^{-} 2 H^{+} (a q) + C l O_{3}^{-} (a q) + 2 e^{-} \to 2 C l O_{2}^{-} (a q) + H_{2} O (l) - ------------------------------------------------------- - 2 C l O_{3}^{-} (a q) \to C l O_{2}^{-} (a q) + C l O_{4}^{-} (a q) E_{c e l l}^{\circ} = 0.33 - 0.36 = - 0.03 E_{c e l l}^{\circ} = \frac{R T}{2 F} I n K \Rightarrow - 0.03 = \frac{0.06}{2} log K \Rightarrow K = 0.1 From the question [C l O_{3}^{-}] = 0.1 M \begin{matrix} 2 C l O_{3}^{-} & ⇌ & C l O_{4}^{-} + & C l O_{2}^{-} 0.1 - 2 x & x & x \end{matrix} \frac{x^{2}}{(0.1 - 2 x)^{2}} = \frac{1}{10} \Rightarrow 3.16 x = 0.1 - 2 x \Rightarrow 5.16 x = 0.1 \Rightarrow x = \frac{0.1}{5.16} \Rightarrow \frac{1}{x} = 51.6$

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Similar questions

Q. The chlorate ion can disproportionate in basic solution according to reaction,

2 C l O_{3}^{-} ⇌ C l O_{2}^{-} + C l O_{4}^{-}

what is the equilibrium concentration of perchlorate ions from a solution initially at

0.1 M

in chlorate ions at

298 K

E_{C l O_{4}^{-} | C l O_{3}^{-}}^{\circ} = 0.36 V a n d E_{C l O_{3}^{-} | C l O_{2}^{-}}^{\circ} = 0.33 V a t 298 K

.

E_{C l O_{4}^{-} / C l O_{3}^{-}}^{o}

E_{C l O_{3}^{-} / C l O_{2}^{-}}^{o}

+ 0.36 V

+ 0.33 V

respectively. The equilibrium concentration of per chlorate ion for the given reaction would be:

2 C l O_{3}^{-} ⇌ C l O_{2}^{-} + C l O_{4}^{-}

t = 0

Q. The concentration of the

O H^{-}

ions present in a solution having the pH value 2 at 298 K is ______.

18^{\circ} C

the mobilities of

N H_{4}^{+}

C l O_{4}^{-}

6.6 \times 10^{- 4}

5.7 \times 10^{- 4} c m^{2} v o l t^{- 1} s e c^{- 1}

at infinite dilution. The equivalent conductance of ammonium chlorate solution is:

At $18^{o} C$ , the mobilities of $N H {_{4}}^{+}$ and $C l O {_{4}}^{-}$ ions are $6.6 \times 10^{- 4}$ and $5.7 \times 10^{- 4} c m^{2} v o l t^{- 1} s e c^{- 1}$ respectively, at infinite dilution.

The equivalent conductance of ammonium chlorate solution is :(in $m h o c m^{2}$ )

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