Question

The coefficient of linear expansion of copper is 17 × 10^–6/°C and its temperature coefficient of resistance is 42.5 × 10^–4°C^–1. If the resistivity of copper at 0°C be 1.55 × 10^–6 Ω. cm, then what will be its resistivity at 100°C?

Answer 1

Dear student
$$\begin{gathered} formulaofresistivityis \\ \rho \left(t\right)={\rho }_0(1+\alpha ∆T) \\ \rho \left(t\right)=1.55\times {10}^{-6}(1+42.5\times {10}^{-4}\times 100) \\ \rho \left(t\right)=1.55\times {10}^{-6}\times 1.425=2.21\times {10}^{-6}\Omega \times cm \\ Regards \end{gathered}$$