The complement of $(90^{o} - a)$ is :

- a

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90^{o} + a

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90^{o} - a

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a

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Solution

The correct option is D $a$
Let the complement be $y$ .
We know, two angles are complementary if their sum is $90^{\circ}$ .
$∴ 90^{\circ} - a + y = 90^{\circ} \Rightarrow y = a$ .
Hence, option $D$ is correct.

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Similar questions

90^{o} - a

(90^{o} - y)

A B C D ∠ B = 90^{o}

A D^{2} = A B^{2} + B C^{2} + C D^{2}

∠ A C D = 90^{o}

A B C D, ∠ B = 90^{o}

∠ D = 90^{o}

2 {A C}^{2} - {A B}^{2} = {B C}^{2} + {C D}^{2} + {D A}^{2}

A + B = 90^{o}

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