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Question

The compound (A) having molecular formula C3H3Cl with alcoholic KOH gives compound (B) with mol formula C3H6 (B) compound with HBr undergoes addition reaction to form C. Identify A,B,C and explain the reactions

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Solution

The formula of A is C3H7Cl. A undergoes reaction with alco KOH giving compound B, so B is an alkene which isconfirmed by its formula (C3H6). So A is an alkyl halide. B undergoes addition reactionwith HBr, according to Markonikoff rule to give product C, where is an alkyl bromide.The reactions areCH3CH2CH2Cl - HCl alc KOH CH3CH=CH2 HBr CH3CH(Br)CH3 A B CThus A= Propyl chlorideB= PropeneC= 2-Bromo propane

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