The compound a on treatment with Na gives B, and with ${P C I}_{5}$ gives C, B and C react together to give diethyl ether, A, B and C are in the order?

C_{2} H_{5} O H, C_{2} H_{6}, C_{2} H_{5} C l

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C_{2} H_{5} O H, C_{2} H_{5} C I, C_{2} H_{5} O N a

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C_{2} H_{5} O H, C_{2} H_{5} O N a, C_{2} H_{5} C l

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C_{2} H_{5} C I, C_{2} H_{6}, C_{2} H_{5} O H

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Solution

The correct option is C $C_{2} H_{5} O H, C_{2} H_{5} O N a, C_{2} H_{5} C l$
$A N a - - \to B P C l s - -- \to C$
One of $B$ & $C$ must be $E t - O N a$ & other $E t - C l$
$E t O N a$ on reaction $P C l_{3}$ gives $E t C l$
$∴ B = E t O N a$
$C = E t - C l$
Hence A must be $E t - O H$

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