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Valency and Oxidation State

The compound ...

Question

The compound ${({N H}_{3})}_{3} C r O_{4}$ has peroxy linkage if oxidation number of $C r$ is $+ 4$ .
If true enter 1, else enter 0.

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Solution

${({N H}_{3})}_{3} C r O_{4}$
Let us take oxidation number of $O = x$
Then, $0 + 4 - 4 x$ ; $x = - 1$
Thus, oxygen atoms are in the form of peroxy linkage.
The compound can be written as $({N H}_{3})_{3} C r (O_{2})_{2}$ .

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