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Standard XII

Chemistry

Conductance of Electrolytic Solution

The conductiv...

Question

The conductivity of $0.1 N$ $N a O H$ solution is $0.022 s / c m$ . When equal volume of the $0.1 N$ $H C l$ solution is added, the conductivity of resultant solution decreases to $0.0055 s / c m$ . The equivalent conductivity in s-cm/equivalent of $N a C l$ solution is:

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Solution

Solution:-
As we know that,
$Λ = \frac{k \times 1000}{N}$
Whereas,
$Λ =$ Equivalent conductivity
$N =$ Normality
$k =$ Conductivity
$N a O H + H C l$ gives $2$ free electrons
Therefore,
$Λ = 2 \times \frac{0.0055 \times 1000}{0.1}$
$\Rightarrow Λ = 110 S - c m^{2} / e q .$
Hence the equivalent conductivity of $N a C l$ solution is $110 S - {c m}^{2} / e q u i v a l e n t$ .

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Similar questions

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The conductivity of 0.1 N NaOH solution is 0.022 s/cm . When equal volume of the 0.1 N HCl solution is added, the conductivity of resultant solution decreases to 0.0055 s/cm. The equivalent conductivity in s-cm/equivalent of NaCl solution is:

Solution:- As we know that,Λ=k×1000NWhereas,Λ= Equivalent conductivityN= Normalityk= ConductivityNaOH+HCl gives 2 free electronsTherefore,Λ=2×0.0055×10000.1⇒Λ=110S−cm2/eq.Hence the equivalent conductivity of NaCl solution is 110S−cm2/equivalent.

The conductivity of $0.1 N$ $N a O H$ solution is $0.022 s / c m$ . When equal volume of the $0.1 N$ $H C l$ solution is added, the conductivity of resultant solution decreases to $0.0055 s / c m$ . The equivalent conductivity in s-cm/equivalent of $N a C l$ solution is: