The coordination number and oxidation number of the central metal ion in the complex $(N H_{4})_{2} [P t (C l)_{6}]$ is :

C . N . = 8, O . N . = + 4

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C . N . = 6, O . N . = + 4

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C . N . = 4, O . N . = + 4

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C . N . = 6, O . N . = + 2

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Solution

The correct option is B $C . N . = 6, O . N . = + 4$
The complex dissociate as $[P t (C l)_{6}]^{2 -} and 2 N H_{4}^{+}$ .
The central metal atom in coordination sphere is attached to 6 $C l^{-}$ ligands. Thus, the coordination number is 6.
Oxidation state of Pt in coordination compound is
$x + (- 1) \times 6 = - 2$
$x - 6 = - 2$
$x = + 4$

Hence, option (b) is correct.

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The coordination number and oxidation number of the central metal ion in the complex (NH4)2[Pt(Cl)6] is :

The coordination number and oxidation number of the central metal ion in the complex $(N H_{4})_{2} [P t (C l)_{6}]$ is :