The correct bond order in the following species is :

O_{2}^{-} < O_{2}^{+} < O_{2}^{2 +}

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O_{2}^{2 +} < O_{2}^{+} < O_{2}^{-}

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O_{2}^{2 +} < O_{2}^{-} < O_{2}^{+}

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$O_{2}^{+} < O_{2}^{-} < O_{2}^{2 +}$

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Solution

The correct option is A $O_{2}^{-} < O_{2}^{+} < O_{2}^{2 +}$
$Bond order of O_{2}^{-} = 1.5$
$Bond order of O_{2}^{+} = 2.5$
$Bond order of O_{2}^{2 +} = 3$

The bond order increases as the stability of the species increases when an electron from the anti-bonding orbital is removed.

$∴ O_{2}^{-} < O_{2}^{+} < O_{2}^{2 +}$

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