Question

The correct increasing order of the oxidation states of nitrogen in $NO,N_{2}O,N{O}_2\text{and}{N}_2{O}_3$ is:

• A. $N{O}_2<NO<N_2{O}_3<N_{2}O$
• B. $N_{2}O<NO<N_2{O}_3<N{O}_2$
• C. $N{O}_2<N_2{O}_3<NO<N_{2}O$
• D. $N_{2}O<N_2{O}_3<NO<N{O}_2$

Answer 1

The correct option is B

$N_{2}O<NO<N_2{O}_3<N{O}_2$

Correct order of oxidation state of nitrogen in oxides of nitrogen is following:
${\stackrel{+1}{N}}_{2}O<\stackrel{+2}{N}O<{\stackrel{+3}{N}}_2{O}_3<\stackrel{+4}{N}{O}_2$