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Question

The correct order of bond angles in H2S,NH3,BF3 and SiH4 is:

A
H2S<SiH4<NH3<BF3
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B
NH3<H2S<SiH4<BF3
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C
H2S<NH3<SiH4<BF3
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D
H2S<NH3<BF3<SiH4
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Solution

The correct option is C H2S<NH3<SiH4<BF3
The correct order = increasing order of Bond angle.
H2S<NH3<SiH4<BF3
H2S,NH3,SiH4 are sp3 hybridized with 2lp, 1lp, 0lp respectively.
Greater the number of lone pairs, smaller is the bond angle due to lp-bp repulsions.

955533_522846_ans_8d091e756cfa4110b13be4d152058e55.png

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