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Byju's Answer
Standard XII
Chemistry
Repulsions
The correct o...
Question
The correct order of bond angles in
H
2
S
,
N
H
3
,
B
F
3
and
S
i
H
4
is:
A
H
2
S
<
S
i
H
4
<
N
H
3
<
B
F
3
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B
N
H
3
<
H
2
S
<
S
i
H
4
<
B
F
3
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C
H
2
S
<
N
H
3
<
S
i
H
4
<
B
F
3
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D
H
2
S
<
N
H
3
<
B
F
3
<
S
i
H
4
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Solution
The correct option is
C
H
2
S
<
N
H
3
<
S
i
H
4
<
B
F
3
The correct order = increasing order of Bond angle.
H
2
S
<
N
H
3
<
S
i
H
4
<
B
F
3
H
2
S
,
N
H
3
,
S
i
H
4
are
s
p
3
hybridized with 2lp, 1lp, 0lp respectively.
Greater the number of lone pairs, smaller is the bond angle due to lp-bp repulsions.
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