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Question

The correct order of bond lengths is:

A
O+2>O22>O2
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B
O2>O+2>O22
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C
O22>O2>O+2
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D
O+2>O2>O22
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Solution

The correct option is C O22>O2>O+2
Molecular orbital configuration for O+2 is (σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px)2(π2py)2 (π2px)1(π2py)0 (σ2pz)0
For O+2,bond order=612=2.5

Molecular orbital configuration for O2 is
(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px)2(π2py)2 (π2px)2(π2py)1 (σ2pz)0
For O2, bond order=632=1.5

Molecular orbital configuration for O22
(σ1s)2 (σ1s)2 (σ2s)2 (σ2s)2 (σ2pz)2 (π2px)2(π2py)2 (π2px)2(π2py)2 (σ2pz)0
For O22, bond order=642=1.0

Thus, the order of bond orders is:
O+2>O2>O22

We know that, Bond order1bond length

So, the correct order of bond lengths will be:
O22>O2>O+2

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