Question

The correct order of equivalent conductance at infinite dilution for $LiCl$, $NaCl$, and $KCl$ would be:

• A. $KCl>NaCl>LiCl$
• B. $LiCl>NaCl>KCl$
• C. $LiCl>KCl>NaCl$
• D. $LiCl\cong NaCl>KCl$

Answer 1

The correct option is A $KCl>NaCl>LiCl$

As atomic size of the atom increases hydration energy decreases
in the order: $L{i}^{+}>N{a}^{+}>K^{+}$.
Hydration makes the cation heavier so mobility decreases in the following order: $K^{+}>N{a}^{+}>L{i}^{+}$
As equivalent conductance at infinite dilution is directly proportional to mobility hence the correct order is:
$KCl>NaCl>LiCl$