Question

The correct order of hybridisation of the central atom in the following species $N{H}_3$, ${\left[PtC{l}_4\right]}^{2-}$, $PC{l}_5$ and $BC{l}_3$

• A. d${sp}^2$ , d${sp}^3$ , ${sp}^2$,${sp}^3$
• B. ${sp}^3$, d${sp}^2$, ${sp}^3$d , ${sp}^2$
• C. d${sp}^2$,${sp}^2$,${sp}^3$,d${sp}^3$
• D. d${sp}^2$,${sp}^3$,${sp}^2$,d${sp}^3$

Answer 1

The correct option is B

${sp}^3$, d${sp}^2$, ${sp}^3$d , ${sp}^2$

$Pt$ would form an inner orbital d complex and $P$ would form an outer orbital d complex.
This eliminates all the other options and you have b as the correct option.