Question

The correct order of increasing s-character (in percentage) in the hybrid orbitals of the given molecules/ions is (assume all hybrid orbitals are exactly equivalent) :
$:C{H}_{2}Xe{F}_{4}Br{F}_{3}NC{l}_3:CC{l}_2$
I II III IV V

• A. II < III < IV < I = V
• B. I > V > III > IV > II
• C. III < II < I < V < IV
• D. II < IV < III < I < V

Answer 1

The correct option is A II < III < IV < I = V

The hybridisation and percentage s-character of given molecules/ions are respectively:
$:C{H}_2=s{p}^2,33.33\%$

$Xe{F}_4=s{p}^3{d}^2,16.67\%$

$Br{F}_3=s{p}^{3}d,20\%$

$NC{l}_3=s{p}^3,25\%$

$:CC{l}_2=s{p}^2,33.33\%$

Option A is correct.