The correct order of the stoichiometries of $A g C l$ formed when $A g N O_{3}$ in excess is treated with the complexes : $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is:

1 A g C l, 3 A g C l, 2 A g C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 A g C l, 1 A g C l, 2 A g C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 A g C l, 2 A g C l, 1 A g C l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 A g C l, 3 A g C l, 1 A g C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $3 A g C l, 2 A g C l, 1 A g C l$
$[C o (N H_{3})_{6}] . C l_{3} + 3 A g N O_{3} \to 3 A g C l$

$[C o (N H_{3})_{5} C l] . C l_{2} + 2 A g N O_{3} \to 2 A g C l$

$[C o (N H_{3})_{4} C l_{2}] . C l + A g N O_{3} \to A g C l$

Thus the correct order of stoichiometries of $A g C l$ formed when $A g N O_{3}$ is added in excess to the above mentioned complexes will be 3, 2 and 1.

Suggest Corrections

Similar questions

Th correct order of the stochiometrics of AgCl formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is

Q. The correct order of the stoichiometries of

A g C l

formed when

A g N O_{3}

in excess is treated with the complexes:

C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}

respectively is:

Q. When

0.1

m o l

C o {C l}_{3} {(N H_{3})}_{5}

is treated with excess of

A g N O_{3},

0.2

mole of

A g C l

are obtained. The conductivity of solution will correspond to

C o C l_{3} .3 N H_{3}

does not form any precipitate with excess

{A g N O}_{3}

solution, whereas 1 mole of

C o C l_{3} .5 N H_{3}

gives two moles of

A g C l

with excess

{A g N O}_{3}

. The van't Hoff factor for both the compounds respectively are:

Join BYJU'S Learning Program

The correct order of the stoichiometries of AgCl formed when AgNO3 in excess is treated with the complexes : CoCl3.6NH3,CoCl3.5NH3,CoCl3.4NH3 respectively is:

The correct option is C 3 AgCl, 2 AgCl, 1 AgCl[Co(NH3)6].Cl3 + 3AgNO3 → 3AgCl [Co(NH3)5Cl].Cl2 + 2AgNO3 → 2AgCl [Co(NH3)4Cl2].Cl + AgNO3 → AgCl Thus the correct order of stoichiometries of AgCl formed when AgNO3 is added in excess to the above mentioned complexes will be 3, 2 and 1.

The correct order of the stoichiometries of $A g C l$ formed when $A g N O_{3}$ in excess is treated with the complexes : $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is: