The correct stability order for the following species is:

(I I) > (I V) > (I) > (I I I)

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(I) > (I I) > (I I I) > (I V)

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(I I) > (I) > (I V) > (I I I)

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(I) > (I I I) > (I I) > (I V)

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Solution

The correct option is D $(I) > (I I I) > (I I) > (I V)$
The correct stability order for the following species is
$I > I I I > I I > I V$

In $I s t$ the lone pair on oxygen stabilises the carbocation as well as it is tertiary carbocation, hence more stable.

The correct order of the stability of carbocations is tert alkyl > sec alkyl > primaryalkyl > methyl carbonium ion.

When an electron donating group (+I effect) present, the stability of carbocation increases.

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The correct order for decreasing stability of the following free radicals is

In the following molecules:
$C H_{3} B r, C H_{3} F, C H_{3} C l, C H_{3} I I, I I, I I I, I V$
The correct order of dipole moment will be:

K_{2} C O_{3} (I), M g C O_{3} (I I), C a C O_{3} (I I I), B e C O_{3} (I V)

The stability of carbanions in the following

i) $R C \equiv ⊖ C$

ii)

iii) $R_{2} C = ⊖ C H$

iv) $R_{3} C - ⊖ C H_{2}$

is in the order of

- I

- C N

- N O_{2}

- N H_{2}

- F

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