MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Self Induction

The current i...

Question

The current in a coil of $L = 40 m H$ is to be increased uniformly from $1 A$ to $11 A$ in $4$ milliseconds. The induced e.m.f. will be

A

100 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

0.4 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

440 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

40 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $100 V$
$e = \frac{L d I}{d t}$
$= \frac{40 \times 10^{- 3} (11 - 1)}{4 \times 10^{- 3}}$
$= 100 V$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The coefficient of mutual inductance of two coils is

5 H .

The current through the primary coil is reduced to zero value from

3 A

1

millisecond. The induced e.m.f. in the secondary coil will be :

0.1 s

, the current in a coil increases from

1 A

1.5 A

. If inductance of coil is

60 m H

, then induced current in external resistance of

3 Ω

Q. Define coefficient of mutual induction. If in the primary coil of a transformer, the current decreases from

0.8 A

0.2 A

4

milliseconds, calculate the induced e.m.f in the secondary coil. Mutual inductance is

1.76 H

Q. The back e.m.f. induced in a coil, when current changes from 1 ampere to zero in one millisecond, is 4 volts, the self inductance of the coil is

Q. If a current increases from zero to one ampere in 0.1 second in a coil of 5 mH, then the magnitude of the induced e.m.f. will be

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Self and Mutual Inductance

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon