The cylindrical tube of a spray pump has radius of 5cm, one end of which has 10 fine holes each of radius 0.1cm. If the speed of liquid in the tube is 1m/s, the speed of the ejection of the liquid through the holes is
A
125m/s
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B
250m/s
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C
450m/s
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D
500m/s
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Solution
The correct option is B250m/s Given, radius of pipe R=5cm
Area of pipe A1=πR2=π(5)2×10−4m2
Radius of one fine hole =r=0.1cm
Area of 10 fine holes = 10×πr2 =10×π(0.1)2×10−4m2
Speed of liquid in tube v1=1m/s
Let speed of ejection of liquid through the holes =v2
Using continuity equation, A1V1=A2V2 π(5)2×10−4×(1)=10×π(0.1)2×10−4×v2 ⇒v2=250m/s