The decreasing order of the stability of the ions:
(I) $C H_{2} - + C H - C H_{3}$
(II) $C H_{3} - + C H - O C H_{3}$
(III) $C H_{3} - + C H - C O C H_{3}$

I > I I > I I I

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I I I > I I > I

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I I > I I I > I

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I I > I > I I I

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Solution

The correct option is D $I I > I > I I I$
The electron donating groups help in the dispersal of positive change throughout the chain.
As $O C H_{3}$ is the most neucliophilic group therefore is most dispersal of charge and $C O C H_{3}$ is the least neucleophitic group therefore there is least dispersal of charge. More is the dispersal of charge, greater is the siability of the carbon atom.
So, the stability order according to the nucleophilicity order is
${C H}_{3} - + C H - O {C H}_{3} > {C H}_{3} - + C H - {C H}_{3} > {C H}_{3} - + C H - C O C H_{3}$
Option: $D$

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