The density of seawater is $1024 k g / m^{3}$ . The pressure at a depth of $5 m$ below the surface of the sea is___ $N / m^{2}$

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Solution

Depth of the point $h$ = $5 m$

Density of sea water $ρ$ = $1024 k g / m^{3}$

Acceleration due to gravity = $g = 10 m / s^{2}$

Pressure = $ρ g h$

= $1024 \times 10 \times 5$

Pressure = $51200 N / m^{2}$

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The density of seawater is 1024 kg/m3. The pressure at a depth of 5 m below the surface of the sea is___ N/m2

Depth of the point h = 5 m Density of sea water ρ = 1024 kg/m3 Acceleration due to gravity = g = 10 m/s2 Pressure = ρgh = 1024×10×5 Pressure = 51200 N/m2

The density of seawater is $1024 k g / m^{3}$ . The pressure at a depth of $5 m$ below the surface of the sea is___ $N / m^{2}$

Depth of the point $h$ = $5 m$

Density of sea water $ρ$ = $1024 k g / m^{3}$

Acceleration due to gravity = $g = 10 m / s^{2}$

Pressure = $ρ g h$

= $1024 \times 10 \times 5$

Pressure = $51200 N / m^{2}$