The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
2520 m2
We have: (l -- b) = 23 and 2 (l + b) = 206 or (l + b) = 103
Solving the two equations, we get ⇒ l = 63 and b = 40
∴ Area = (l ×b) = (63 × 40) m2 = 2520 m2