The difference between the length and breadth of a rectangle is $23 m$ . If the perimeter is $206 m$ then the area is

1520 m^{2}

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2520 m^{2}

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2420 m^{2}

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None

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Solution

The correct option is B $2520 m^{2}$
Let breadth $= x$ .
Length $= x + 23$ .
Perimeter $= 206 m$ .
$2 (x + 23 + x) = 206$
$2 x + 23 = 103$
$x = 40$
Area $= l \times b = 63 \times 40$
$= 2520 m^{2}$

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The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

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