Question

The dipole moment of hydrogen chloride, with bond distance $127$ pm, is $1.03D$. The percent ionic character of its bond is about:

Answer 1

Theoritical dipole moment $=q\times d=1.6\times {10}^{-19}\times 127\times {10}^{-12}=203.2\times {10}^{-31}$ Coloumb meter $=6.1D$ (as $1D=3.33\times {10}^{-30}C.m$)

So, % ionic character $=\frac{observeddipolemoment}{theoreticaldipolemoment}\times 100=\frac{1.03}{6.1}\times 100=17\%$