The displacement x of a body having relation with time as $x = 3 t^{2} - 6 t + 7$ , then distance covered by body in first two second is [where x is in metre and t is in second]

Zero

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6 m

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3 m

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9 m

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Solution

The correct option is A Zero
The relation between time and the displacement is given by
$x = 3 t^{2} - 6 t + 7$
The distance covered by a body in the first two seconds is
$d = [3 t^{2} - 6 t + 7]_{0}^{2}$
$d = (3 \times 2 \times 2 - 6 \times 2 + 7) - (3 \times 0 \times 0 - 6 \times 0 + 7)$
$d = (12 - 12 + 7) - (0 - 0 + 7)$
$d = 7 - 7$
$d = 0 m$
The correct option is A.

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The displacement x of a body having relation with time as x=3t2−6t+7, then distance covered by body in first two second is [where x is in metre and t is in second]

The correct option is A ZeroThe relation between time and the displacement is given byx=3t2−6t+7The distance covered by a body in the first two seconds isd=[3t2−6t+7]20d=(3×2×2−6×2+7)−(3×0×0−6×0+7)d=(12−12+7)−(0−0+7)d=7−7d=0mThe correct option is A.

The displacement x of a body having relation with time as $x = 3 t^{2} - 6 t + 7$ , then distance covered by body in first two second is [where x is in metre and t is in second]