Question

The distance x (in $\mu$m) covered by a molecule starting from point A at time t = 0 and stopping at another point B is given by the equation
$x=t^2(2-\frac{t}{3})$
The distance between A and B (in $\mu$m) is closed to

• A. 10.7
• B. 20.7
• C. 40.7
• D. 50.7

Answer 1

The correct option is A 10.7

At $t=0$, position is $0$, and the velocity is given by $v=4t-t^2$
Velocity becomes zero at $4s$.

At this instant the position is $10.7$, distance between $A$ and $B$ is $10.7$