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Question

The driver of a train traveling at 40 m s1 applies the brakes as the train enters a station. The train slows down at a rate of 2 m s2. The distance traveled by train before stopping is:

A
200 m
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B
300 m
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C
400 m
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D
500 m
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Solution

The correct option is C 400 m
Assumption: Initial direction of velocity is positive.
Given:
Initial speed, u=40 ms1
Acceleration, a=2 ms2
Acceleration is negative because it is opposite to the direction of initial velocity.
As the train finally stops, final velocity, v=0

Let the distance traveled by train before stopping be s.

Using equation of motion,
v2=u2+2as
Substituting values,
02=402+(2×2×s)
Solving, we get:
s=+400 m

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