The ease of hydrolysis in the compounds CH_3COCl(1),CH_3-CO-O-COCH_3(2),CH_3COOC_2H_5(3) & CH_3CONH_2(4) is of tyhe order- (a)1>2>3>4 (b)4>3>2>1 (c)1>2>4>3 (d)2>1>4>3

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Q. The hybridisation of carbons

C_{1}

and

C_{3}

in the compound:
1 2 3 4

C H_{3} - C H = C H - C H_{3}

Consider the following carbocations

(1) $C H_{3} - \oplus C H_{2}$ (2) $C H_{2} = \oplus C H$ (3) $C H_{2} = C H - \oplus C H_{2}$ (4) $C_{6} H_{5} - \oplus C H_{2}$ stability of these carbocations in decreasing order is

C H_{3} - N H | | C (1) - N H_{2}

C H_{3} - C H_{2} (2) - N H_{2}

(C H_{3})_{2} (3) N H

C H_{3} - O | | C (4) - N H_{2}

The correct order of the basicities of the following compounds is:

Q. Arrange in decreasing order of basicity:

Q. Four solutions of

N H_{4} C l

are taken with concentrations

1 M, 0.1 M, 0.01 M a n d 0.001 M

. Their degree of hydrolysis are

h_{1}, h_{2}, h_{3}

and

h_{4}

. What is the decreasing order of degree of hydrolysis ?

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