A spherical shell of radius 10 cm is carrying a charge q. if the electric potential at distances 5 cm, 10 cm and 15 cm from the centre of the spherical shell is $V_{1}, V_{2} a n d V_{3}$ respectively, then

Q. In a space, potential

(V)

is given by

V = {log}_{e} (x y)

, where

V, x, y

are in SI units. The angle between

\to E

X

-axis at point

(6, 6 \sqrt{3}) m

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The electric field in a region is given by →E=(Ax+B)^i, where E is in NC−1 and x is in metres. The values of constants are A=20 SI unit and B=10 SI unit. If the potential at x=1, is V1, and that at x=−5 is V2, then V1−V2

The correct option is B 180 VGiven, →E=(Ax+B)^i ⇒E=20x+10 Now, V=−∫Edx, ⇒V1−V2=−∫1−5(20x+10)dx =−20[x22]1−5−10[x]1−5 ∴V1−V2=180 V Hence, (C) is the correct answer.

The electric field in a region is given by $\to E = (A x + B)^i$ , where $E$ is in ${NC}^{- 1}$ and $x$ is in metres. The values of constants are $A = 20$ SI unit and $B = 10$ SI unit. If the potential at $x = 1$ , is $V_{1}$ , and that at $x = - 5$ is $V_{2}$ , then $V_{1} - V_{2}$