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Question

The electric field in a region is given by E=35E0^j with E0=2×103NC1 Find the flux of this field through a rectangular surface of area 0.2m2 parallel to the YZ plane.

A
320Nm2C1
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B
240Nm2C1
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C
400Nm2C1
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D
none of these
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Solution

The correct option is B none of these
The electric flux , ϕ=E.^ndS
Since the surface is parallel to YZ plane so the normal unit vector will be along x-axis i.e ^n=^i
Thus, ϕ=(3/5)E0^j.^i(0.2)=0 (as ^j.^i=0)
Thus, option D will correct.

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