Flux is due to charges enclosed per ϵ0 ∴ Total flux =(−14+78.85−56)nC/ϵ0 =8.85×10−9C×4π4πϵ0=8.85×10−9×9×109×4π =1000.4 Nm2/C i..e. 1000 Nm2C−1
In the figure shown, the particles have charges q1 = −q2 = 300 nC and q3 = −q4 =200 nC, and distance a = 5.0 cm. What are the (A) magnitude and (B) angle (relative to the +x direction) of the net force on particle 3?