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Question

The EMF of the cell
M|Mn+(0.02 M)||H+(1 M)|H2(g)(1 atm),Pt at 25C is 0.81 V. Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76 V

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Solution

M(s) Mn+(aq) + ne ----1
nH+(1M)+ ne n2H2(g) ---2
Adding 1 and 2 we get,
nH+(1M)+ M(s) Mn+(0.02M) + n2H2(1atm)
E=0.81
Eo = EoR EoL
= 0-(-0.76)
= 0.76
E = Eo 0.059nlog(1×0.02)
0.81 = 0.76 0.059nlog(2×102)
0.05 = 0.059n × (2+log2)
n=2


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