The EMF of the following cells are: Cu|Cu2+(1M)||Ag+(1M)|Ag,E0=0.46V Zn|Zn2+(1M)||Cu2+(1M)|Cu,E0=1.10V The EMF of the cell Zn|Zn2+(1M)||Ag+(1M)|Ag will be:
A
1.56 V
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B
0.64 V
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C
-1.56 V
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D
2.02 V
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Solution
The correct option is A 1.56 V Cu+2Ag+→2Ag+Cu+2E01=0.46V