The emperical formula of a compound is $C H_{2} O$ and its molecular weight is 90. What is the molecular formula of the compound?

C_{2} H_{2} O_{2}

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C_{2} H_{4} O_{2}

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C H_{2} O_{2}

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C_{3} H_{6} O_{3}

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Solution

The correct option is D $C_{3} H_{6} O_{3}$
$M o l e c u l a r f o r m u l a = n \times e m p e r i c a l f o r m u l a$
$n = \frac{M o l e c u l a r f o r m u l a w e i g h t}{e m p e r i c a l f o r m u l a w e i g h t}$
Emperical formula weight of $C H_{2} O$ is $30 (12 + 2 + 16)$
Molecular formula weight is 90
So,
$n = \frac{90}{30} = 3$
$M o l e c u l a r f o r m u l a = 3 \times C H_{2} O$
Hence molecular formula is $C_{3} H_{6} O_{3}$
Option D is correct answer.

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