Question

The energy od proton in a light of wavelength 6000 $\mathring{A}$ is :
$(h=6.63\times {10}^{-34}$ $Js,$ $c=3\times {10}^{8}m/s)$

• A. $6.81\times {10}^{-19}J$
• B. $5.61\times {10}^{-19}J$
• C. $3.31\times {10}^{-19}J$
• D. $2.31\times {10}^{-19}J$

Answer 1

The correct option is C $3.31\times {10}^{-19}J$

$E=\frac{hc}{\alpha }$

$=\frac{6.63\times {10}^{-34}\times 3\times {10}^8}{6000\times {10}^{-10}}$

$=3.31\times {10}^{-19}J$