Question

The energy of an electron in an excited hydrogen atom is $-3.4eV$. Then, according to Bohr's Theory, the angular momentum of this electron, in $Js$, is

• A. $2.11\times {10}^{-34}$
• B. $3\times {10}^{-34}$
• C. $1.055\times {10}^{-34}$
• D. $0.5\times {10}^{-34}$

Answer 1

The correct option is A $2.11\times {10}^{-34}$

As per the energy equation, $n=2$ has $-3.4eV$
Therefore, Angular momentum (L) is $=\frac{2h}{2\pi }=\frac{6.625\times {10}^{-34}}{3.14}\therefore L=2.11\times {10}^{-34}Js$