Question

The energy of an electron in excited hydrogen atom is -3.4 eV. Then according to Bohr's theory the angular momentum of the electron in J-s is

• A. $2.11\times {10}^{-34}$
• B. $3\times {10}^{-34}$
• C. $2\times {10}^{-34}$
• D. $0.5\times {10}^{-34}$

Answer 1

The correct option is A

$2.11\times {10}^{-34}$

$n=2\Rightarrow J_2=\frac{2h}{2\pi }=\frac{h}{\pi }=\frac{6.62\times {10}^{-34}}{3.14}$

$=2.11\times {10}^{-34}\text{J-sec}$