Question

The energy of electron in an excited hydrogen atom is $-3.4eV$. Its angular momentum according to Bohr's theory will be

• A. $\frac{h}{\pi }$
• B. $\frac{h}{2\pi }$
• C. $\frac{3h}{2\pi }$
• D. $\frac{3}{2\pi h}$

Answer 1

Answer: (A)

$\frac{h}{\pi }$

Given,

$E=-3.4eV$

Energy, $E=\frac{-13.6eV}{n^2}$

$n^2=\frac{-13.6eV}{-3.4eV}$

$n^2=4$

$n=2$

From Bohr's theory, the angular momentum id given by

$L=\frac{nh}{2\pi }$

$L=\frac{\left(2\right)h}{2\pi }$

$L=\frac{h}{\pi }$

The correct option is A.