The enthalpies of combustion of carbon and carbon monoxide are $- 393.5$ and $- 283$ kJ mol $^{- 1}$ respectively. The enthalpy of formation of carbon monoxide per mole is:

- 676.5

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676.5

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110.5

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- 110.5

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Solution

The correct option is D $- 110.5$ kJ
1. $C + O_{2} \to C O_{2} Δ H = - 393.5 k J$
2. $C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 283 k J$

3. $C O_{2} \to C O + \frac{1}{2} O_{2}; Δ H = 283 k J$
Adding 1 and 3,

$C + \frac{1}{2} O_{2} \to C O$ $; - 393 .5 + 283 = - 110.5 k J$

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